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(2/61)(3/61)(4/61)(5/61)(6/61)(7/61)(8/61)(9/61... Link

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an=n+161a sub n equals the fraction with numerator n plus 1 and denominator 61 end-fraction The full product is: (2/61)(3/61)(4/61)(5/61)(6/61)(7/61)(8/61)(9/61...

: In the context of "proper review" or limit theory, an infinite product ∏anproduct of a sub n converges to a non-zero number only if AI responses may include mistakes